Chapter 10 - Radical Expressions and Equations - Chapter Review - 10-4 Solving Radical Equations - Page 643: 44

$x=.5$

$2x=\sqrt{2-2x}$ $(2x)^2=(\sqrt{2-2x})^2$ $4x^2 = 2-2x$ $4x^2+2x-2 = 2-2x+2x-2$ $4x^2+2x-2 = 0$ $(4x-2)(x+1)=0$ $4x-2=0$ $4x=2$ $4x/4 = 2/4$ $x= .5$ $x+1=0$ $x=-1$ $x=-1$ $2x=\sqrt{2-2x}$ $2*(-1)=\sqrt{2-2*(-1)}$ $-2 = \sqrt {2+2}$ $-2 \ne \sqrt4$ $x=.5$ $2x=\sqrt{2-2x}$ $2*.5=\sqrt{2-2*.5}$ $1 = \sqrt{2-1}$ $1 =\sqrt1$ $1=1$