Answer
see graph
Work Step by Step
The computations below show some of the values of $x$ and $y$ in the given equation, $
y=\sqrt{x-2.5}
.$
If $x=2,$ then
\begin{array}{l}\require{cancel}
y=\sqrt{2-2.5}
\\
y=\sqrt{-0.5}
\\
y=\text{not a real number}
\\\text{(*Note that the square root of negative numbers are imaginary numbers)}
.\end{array}
If $x=2.5,$ then
\begin{array}{l}\require{cancel}
y=\sqrt{2.5-2.5}
\\
y=\sqrt{0}
\\
y=0
.\end{array}
If $x=3.5,$ then
\begin{array}{l}\require{cancel}
y=\sqrt{3.5-2.5}
\\
y=\sqrt{1}
\\
y=1
.\end{array}
If $x=6.5,$ then
\begin{array}{l}\require{cancel}
y=\sqrt{6.5-2.5}
\\
y=\sqrt{4}
\\
y=2
.\end{array}
If $x=11.5,$ then
\begin{array}{l}\require{cancel}
y=\sqrt{11.5-2.5}
\\
y=\sqrt{9}
\\
y=3
.\end{array}
Using the table of values below, the graph of the given function is shown.
