Answer
$a^{2}+9a+1$
Work Step by Step
$(4a^{2}+3a+1)-(3a^{2}-6a)$
Combine like terms:
$4a^{2}-3a^{2}=a^{2}$
$3a+6a=9a$
$1=1$
$a^{2}+9a+1$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-5 Graphing Square Root Functions - Mixed Review - Page 631: 78
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