Answer
$(-3, infinity)$
Work Step by Step
We can't have the square root of a negative number, so $y$'s lowest value is 0.
$0=\sqrt {x+3}$
$0^2=(\sqrt {x+3})^2$
$0= x+3$
$-3=x$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-5 Graphing Square Root Functions - Lesson Check - Page 628: 1
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