Answer
a) $V = 10x^2$
b) $\sqrt {V/10} = x$
c) $2 \leq x \leq 7$ where $x$ is an integer
Work Step by Step
a)
$V = 10*x*x = 10x^2$
b)
$V=10x^2$
$V/10 = 10x^2/10$
$V/10 = x^2$
$\sqrt {V/10} = \sqrt {x^2}$
$\sqrt {V/10} = x$
c)
$\sqrt {V/10} = x$
$\sqrt {40/10} = x$
$\sqrt {4} = x$
$x = 2, -2$ (but we can't have a negative length)
$\sqrt {490/10} = x$
$\sqrt {49} = x$
$x=7, -7$ (but we can't have a negative length)