Answer
$x= 2, -2$
Work Step by Step
$2f^2-8=0$
$x=(-b±\sqrt {b^2-4ac})/2a)$
$x=(±\sqrt {0^2-4*2*8})/2*2)$
$x=(±\sqrt {0+64})/4)$
$x=(±\sqrt {64})/4)$
$x=8/4, -8/4$
$x= 2, -2$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Mixed Review - Page 625: 61
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