Answer
$x=12$
Work Step by Step
$Given:$ $\sqrt (3x) + 10=16$
$\sqrt (3x) + 10 - 10=$$16-10$
$\sqrt (3x)=6$
$Squaring$ $on$ $both$ $sides,$ $3x=36$
$x=36\div3=12$
$x=12$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Lesson Check - Page 623: 1
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