Answer
$106+6\sqrt{77}$
Work Step by Step
$(3\sqrt{11}+\sqrt{7})^2=3\sqrt{11}(3\sqrt{11}+\sqrt{7})+\sqrt{7}(3\sqrt{11}+\sqrt{7})=9\sqrt{121}+3\sqrt{77}+3\sqrt{77}+\sqrt{49}=9\sqrt{121}+6\sqrt{77}+\sqrt{49}=99+7+6\sqrt{77}=106+6\sqrt{77}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Practice and Problem-Solving Exercises - Page 616: 26
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