Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 611: 69

Answer

$\frac{16\sqrt{6a}}{6a}$

Work Step by Step

$\frac{16a}{\sqrt{6a^3}}\longrightarrow$ factor perfect square out of $6a^3$ =$\frac{16a}{\sqrt{a^2\times6a}}\longrightarrow$ multiplication property of square roots =$\frac{16a}{\sqrt{a^2}\times\sqrt{6a}}\longrightarrow$ simplify =$\frac{16/\!\!a}{/\!\!a\sqrt{6a}}\longrightarrow$ multiply numerator and denominator by $\sqrt{6a}$; a cancels in numerator and denominator =$\frac{16}{\sqrt{6a}}\times\frac{\sqrt{6a}}{\sqrt{6a}}\longrightarrow$ simplify =$\frac{16\sqrt{6a}}{6a}$
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