Answer
$64y^2-9=(8y+3)(8y-3)$
Work Step by Step
Remember that the product of the sum and the difference of the same two terms is the difference of their squares.
Since $\sqrt64y^2=8y$ and $\sqrt9=3$
$64y^2-9=(8y+3)(8y-3)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Mixed Review - Page 612: 86
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
