Answer
$t=7$ or $t=-4$
Work Step by Step
$t^2-3t=28$
$t^2-3x-28=0$
$t^2-7t+4t-28=0$
$t(t-7)+4(t-7)=0$
$(t-7)(t+4)=0$
$t=7$ or $t=-4$
The equation has two solutions, $t=7$ or $t=-4$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 575: 21
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