Answer
The solutions of the system are $(1,-2)$ and $(0,-1)$.
Work Step by Step
We are given:
$y=-x=1$
$y=x^2-2x-1$
Graph both equations in the same coordinate plane.
The points of intersection are $(1,-2)$ and $(0,-1)$.
Hence, the solutions of the system are $(1,-2)$ and $(0,-1)$.
