Answer
The solutions of the system are $(1, -8)$ and $(2,-9)$.
Work Step by Step
$y=-x -7$
$y=x^2-4x-5$
Substitute $x +2$ for y:
$-x -7=x^2-4x-5$
$x^2-3x+2=0$
$(x-1)(x-2)=0$
$x-1=0$ or $x-2=0$
$x=1$ or $x=2$
Find corresponding y-values. Use either original equation:
$y=-x-7$
$y=-(1)-7$ or $y=-(2)-7$
$y=-8$ or $y=-9$
The solutions of the system are $(1, -8)$ and $(2,-9)$.