Answer
2 solutions
Work Step by Step
$$ \text{The quadratic formula is given by:}$$ $$ x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
$$ \text{Plugging in the given values:}$$
$$a=1, b=2, c=0$$
$$ x = \frac{-2 \pm \sqrt{2^2-4(1)(0)}}{2(1)}$$
$$\text{Reducing within the radical gives: } $$
$$ x = \frac{-2 \pm \sqrt{4}}{(2)1}$$
$$ \text {This gives: } $$
$$x=0,-2$$