Answer
a) $(-2,6)$
b) $(-6,-2)$
Work Step by Step
a)
$x^2+4x+10 = 0$
$x^2+4x= - 10$
$x^2 + 4x + 4 = -6$
$(x+2)^2 + 6 = 0$
The vertex will be (h,k) where $(x-h)^2+k=0$
The vertex is $(-2,6)$
b)
$x^2+ 12x+34 = 0$
$x^2 + 12x = -34$
$x^2+12x+36= 2$
$(x+6)^2-2 = 0$
The vertex will be (h,k) where $(x-h)^2+k=0$
The vertex is $(-6,-2)$