Answer
$b = \pm \frac{4}{3}$
Work Step by Step
$9b^2=16$
$9b^2-16=0$
$(3b)^2-4^2=0$
$(3b-4)(3b+4)=0$
$3b-4=0$ or $3b+4=0$
$b = \pm \frac{4}{3}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 571: 25
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