Answer
4 ft by 2.5 ft
Work Step by Step
Let w be the width of the table.
The length is 2w−1.
The area is w(2w−1).
Given that the area is 10, solve for w.
$w(2w−1)=10$
$2w^2−w=10$
$2w^2−w−10=10−10$
$2w^2−w−10=0$
$(2w−5)(w+2)=0$
Use the zero product property to solve for w.
2w−5=0 OR w+2=0
2w−5+5=0+5 OR w+2−2=0−2
2w=5 OR w=−2
2w÷2=5÷2 OR w=−2
w=2.5 OR w=−2
Since the width cannot be negative, the width is 2.5 ft. Find the length.
l=2(2.5)−1=5−1=4 ft
