Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 566: 57

Answer

$y=28\;cm$.

Work Step by Step

The given values are Height $h=y$ Bases $b_1=y$ and $b_2=4y$. Area $A=1960\;cm^2$. The given formula is $\Rightarrow A=\frac{1}{2}h(b_1+b_2)$ Substitute all values. $\Rightarrow 1960\;cm^2=\frac{1}{2}y(y+4y)$ Simplify. $\Rightarrow 1960\;cm^2=\frac{1}{2}y(5y)$ $\Rightarrow 1960\;cm^2=\frac{5}{2}y^2$ Multiply the equation by $\frac{2}{5}$ $\Rightarrow \frac{2}{5}\cdot 1960\;cm^2=\frac{2}{5}\cdot\frac{5}{2}y^2$ Simplify. $\Rightarrow 784\;cm^2=y^2$ Take the square root on both sides. $\Rightarrow \sqrt{784\;cm^2}=\sqrt{y^2}$ Simplify. $\Rightarrow 28\;cm=y$.
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