Answer
See the graph
Work Step by Step
$f(x)=-x^2+2x-5$
Find the axis of symmetry and the coordinates of the vertex.
$x=\frac{-b}{2a}=\frac{-2}{2.(-1)}=1$
The axis of symmetry is $x = 1$. So the x-coordinate of the vertex is 1.
Substitute 1 for x to find the y-coordinate of the vertex.
$y=-(1)^2+2(1)-5$
$y=-4$
The vertex is $(1,-4)$
Find two other points on the graph.
$(0,-5)$
$(2,-5)$
Graph the vertex and the points we found.
