Chapter 9 - Quadratic Functions and Equations - 9-1 Quadratic Graphs and Their Properties - Practice and Problem-Solving Exercises - Page 550: 15

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We are given: $y=-\frac{1}{3}x^2$ Make a table of values. $x=-2 \rightarrow y=-\frac{4}{3}$ $x=-1 \rightarrow y=-\frac{1}{3}$ $x=0 \rightarrow y=0$ $x=1 \rightarrow y=-\frac{1}{3}$ $x=2 \rightarrow y=-\frac{4}{3}$ The vertex is $(0,0)$. It is a maximum. The domain is all real numbers. The range is $y \leq 0$.