Answer
$36p^{2}q^{2}$
Work Step by Step
Apply rule: $\qquad (a\cdot b)^{n}=a^{n}\cdot b^{n}$
$(-6pq)^{2}=(-6)^{2}p^{2}q^{2}$
$=36p^{2}q^{2}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - Get Ready! - Page 483: 20
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