Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Lesson Check - Page 531: 3

Answer

$6(2x^{2}+3)(2x+5)$

Work Step by Step

$24x^{3}+60x^{2}+36x+90$ ...factor out the GCF. $=6(4x^{3}+10x^{2}+6x+15)$ ...factor by grouping. $=6[2x^{2}(2x+5)+3(2x+5)]$ ...factor again. $=6(2x^{2}+3)(2x+5)$
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