Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Got It? - Page 530: 2

Answer

$3h(h^{2}+2)(2h+3)$

Work Step by Step

$6h^{4}+9h^{3}+12h^{2}+18h=$ ...factor out the GCF. $=3h(2h^{3}+3h^{2}+4h+6)$ ...factor by grouping. ...(factor out the GCF of each group of two terms) $=3h[h^{2}(2h+3)+2(2h+3)]$ ...factor again ...(factor out the common factor, $(2h+3)$) $=3h(h^{2}+2)(2h+3)$
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