Answer
$(d-10)^{2}$
Work Step by Step
$d^{2}-20d+100=$
...write the last term as a square.
$=d^{2}-20d+10^{2}$
...does middle term equal $2ab$?
$20d=2(d)(10)$
$=d^{2}-2(d)(10)+10^{2}$
...write as the square of a binomial.
$=(d-10)^{2}$