Answer
Two different values are $-34$ and $41$.
$2(r+1)(4r-21)$ and $ (8r-7)(r+6)$.
Work Step by Step
The given expression is
$8r^2+\_r-42$
The standard form of the trinomial is
$ax^2+bx+c$
Where, $a=8,c=-42$ and $b=?$.
Multiply $a$ and $c$.
$ac=8\times (-42)=-336$
Two possible factors are $8\times (-42)$ and $48\times (-7)$.
So the values of $b$ are $8-42=-34$ and $48-7=41$.
The first trinomial is
$\Rightarrow 8r^2-34r-42$
Factor.
$\Rightarrow 2(r+1)(4r-21)$.
The second trinomial is
$\Rightarrow 8r^2+41r-42$
Factor.
$\Rightarrow (8r-7)(r+6)$.
