Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax2+bx+c - Practice and Problem-Solving Exercises - Page 520: 13

Answer

(4g-1)(2g-3)

Work Step by Step

You are given $8g^{2}$-14d+3. Factor it out: $8g^{2}$-2g-12g+3 -break out the middle value- ($8g^{2}$-2g)+(-12g+3) -group the first two and last two terms- 2g(4g-1)-3(4g-1) -Find the GCF of each grouping- (4g-1)(2g-3) -factor out the common term- =(2g-3)(4g-1)
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