Answer
(4g-1)(2g-3)
Work Step by Step
You are given $8g^{2}$-14d+3. Factor it out:
$8g^{2}$-2g-12g+3 -break out the middle value-
($8g^{2}$-2g)+(-12g+3) -group the first two and last two terms-
2g(4g-1)-3(4g-1) -Find the GCF of each grouping-
(4g-1)(2g-3) -factor out the common term-
=(2g-3)(4g-1)