Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-3 Multiplying Binomials - Practice and Problem-Solving Exercises - Page 502: 42

Answer

In the first step, the error is in distributing the products (one term is missing, there should be four). result: $3x^{2}-2x-8$

Work Step by Step

In the first step, the error is in distributing the products (one term is missing, there should be four). It should be $(x-2)(3x+4)$ $=x(3x)+x(4)-2(3x)-2(4)$ $=3x^{2}+4x-6x-8$ ...add like terms. =$3x^{2}-2x-8$
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