Answer
$\$4489.01$.
Work Step by Step
$A=P(1+\frac{r}{n})^{nt}$
The given values are
Principal $P=2000$
Rate of interest $r=4.5\%=0.045$
Number of periods $n=12$
Time $t=18\;yr$
Substitute all values into the formula.
$\Rightarrow A=2000(1+\frac{0.045}{12})^{12\cdot 18}$
Simplify.
$\Rightarrow A=4489.01$
Hence, the account balance after $18\;yr$ is $\$4489.01$.
