Answer
No.
$3\sqrt{4}\neq 4$.
Work Step by Step
$\sqrt{4^{3}}=\sqrt{4^{2}\cdot 4}=4\sqrt{4}$
$\sqrt{4^{3}}-\sqrt{4}=4\sqrt{4}-\sqrt{4}$
... So, factoring out $\sqrt{4}$
$=\sqrt{4}(4-1)$
$=3\sqrt{4}\neq 4$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-5 Rational Exponents and Radicals - Lesson Check - Page 450: 10
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