Answer
$a.\quad 3$
$b.\quad 2$
$c.\quad 4$
$d.\quad 6$
Work Step by Step
$a.$
Recognize that $27=3^{3}$
$\sqrt[3]{27}=\sqrt[3]{3^{3}}=3$
$b.$
Recognize that $32=2^{5}$
$\sqrt[5]{35}=\sqrt[5]{2^{5}}=2$
$c.$
Recognize that $64=4^{3}$
$\sqrt[3]{64}=\sqrt[3]{4^{3}}=4$
$d.$
Recognize that $36=6^{2}$
$\sqrt[2]{36}=\sqrt[2]{6^{2}}=6$