Answer
The aircraft has a kinetic energy of about $11.25 \times 10^9$ joules.
Work Step by Step
The expression $\frac{1}{2}mv^2$ gives the kinetic energy, in joules, of an object with a mass of m kg traveling at a speed of v meters per second.
Substitute the values for m and v into the expression.
$\frac{1}{2}mv^2=\frac{1}{2}( 2.5 \times 10^5 )( 3 \times10^2)^2$
$=\frac{1}{2}\times2.5\times10^5\times3^2\times(10^2)^2$
$=\frac{1}{2}\times2.5\times9\times10^9$
Simplify. Write in scientific notation
$=11.25 \times 10^9$
The aircraft has a kinetic energy of about $11.25 \times 10^9$ joules.
