Answer
a. 343$m^{27}$
b. $\frac{1}{16z^4}$
c. $\frac{1}{9g^8}$
Work Step by Step
To solve :
a. $(7m^{9})^{3}$ = ($7^{3}$)($m^{9\times3})$ = 343$m^{27}$
b. $(2z)^{-4}$ = ($2^{-4}$)($z^{-4})$ = $\frac{1}{2^{4}z^{4}}$ = $\frac{1}{16z^4}$
c. $(3g^{4})^{-2}$ = ($3^{-2}$)($g^{4\times-2})$ = ($3^{-2}$)($g^{-8})$ = $\frac{1}{3^{2}g^{8}}$ = $\frac{1}{9g^8}$
