Answer
-$\frac{240m^{3}}{r}$. OR -240$m^{3}$$r^{-1}$
Work Step by Step
-$m^{2}\times4r^{3}\times12r^{-4}\times5m$
= -$m^{2}\times4r^{3}\times\frac{12}{r^{4}}\times 5m$
= $\frac{(-1\times4\times12\times5)(m^{2+1})}{r^{4-3}}$
=$\frac{-240m^{3}}{r} = -240$m^{3}r^{-1}$