Answer
6$n^{\frac{17}{12}}$
Work Step by Step
2$n^{\frac{2}{3}}$ $\times$ 3$n^{\frac{3}{4}}$ = (2$\times$3)($n^{\frac{2}{3}+\frac{3}{4}}$) = 6$n^{\frac{2}{3}+\frac{3}{4}}$ = 6$n^{\frac{2(4)+3(3)}{12}}$ = 6$n^{\frac{17}{12}}$
This question was solved using the exponential laws.