Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises - Page 422: 44

The answer is -$\frac{27}{400}$

The expression $2^{-4}$$\times$$r^{3}$$\times$$s^{-2}$ can be simplified to $\frac{r^{3}}{2^{4}\times(s)^{2}}$ So, to solve this question, we can plug in r=-3 and s=5 $\frac{r^{3}}{2^{4}\times(s)^{2}}$ = $\frac{(-3)^{3}}{2^{4}\times(5)^{2}}$ = $\frac{-27}{16\times25}$ = $\frac{-27}{400}$