Answer
-2
Work Step by Step
Recall the equation: $a^{-n}= \frac{1}{a^{n}}$. Thus, we simplify this expression and solve:
$a^{3}b^{-1}=\frac{a^{3}}{b}$
We now plug in 2 for a and -4 for b to obtain:
$\frac{2^{3}}{-4}=8/-4=-2$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Lesson Check - Page 421: 5
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