Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-4 Applications of Linear Systems - Practice and Problem-Solving Exercises - Page 391: 17

Answer

$A=-3$ $B=-2$

Work Step by Step

$Ax — 2 By = 6 $ $3 Ax - By = -12 $ Plug in the values for x and y. $2A - 6B =6$ $6A -3B=-12$ Add 3 to both sides of the first equation: $6A - 18B =18$ $6A -3B=-12$ Eliminate: $-15B=30$ $B=-2$ Solve for A $A=-3$
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