Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 383: 35

$y=5$ $x=6$

$y=\frac{2}{3}x+1$ $2x+3y=27$ $-\frac{2}{3}x+y=1$ (1) $2x+3y=27$ (2) Divide both sides of equation (2) by $3$ to obtain: $-\frac{2}{3}x+y=1$ $\frac{2}{3}x+y=9$ ___________________ $2y=10$ $y=5$ $x=6$