Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Practice and Problem-Solving Exercises - Page 376: 35

Answer

The error is in step 2. See below for correction. Solution: $(\displaystyle \frac{7}{51},\frac{133}{51})$

Work Step by Step

Step 1 is good because the second equation has been chosen to be solved for x. Step 2 is faulty, because it does not represent the second equation with x substituted with $21-8y.$ $x$ has been substituted into the first equation instead of into the second. It should be: $7( 21-8y)+5y=14$ $ 147-56y+5y=14\quad$... add $-147$, simplify $-51y=-133$ $y= \displaystyle \frac{133}{51}$ Substitute $y$ in $\quad x=21-8y.$ $x=21-8\displaystyle \cdot\frac{133}{51}$ $x=\displaystyle \frac{1071- 1064}{51}$ $x=\displaystyle \frac{7}{51}$ Solution: $(\displaystyle \frac{7}{51},\frac{133}{51})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.