Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Lesson Check - Page 375: 8

Answer

Second equation, variable $y.$

Work Step by Step

To avoid fractions in the first step (solving one equation for one of the variables) we seek a variable with coefficients 1 or -1. In this case, the variable y in the second equation would be our choice, as its coefficient is $-1.$ $ 6x-y=1\qquad$ ... add $y-1$ $6x-1=y$ And, in the next step, we would substitute $y$ with $6x-1$ and solve for x.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.