Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Got It? - Page 374: 4

Answer

Infinitely many

Work Step by Step

Step 1 Solve one of the equations for one of the variables. $ 6y+5x=8\qquad$ ... subtract 5x $ 6y=8-5x\qquad$ ... divide with 6 $y=\displaystyle \frac{4}{3}-\frac{5}{6}x$ Step 2 Substitute $\displaystyle \frac{4}{3}-\frac{5}{6}x$ for $y$ in the other equation, and solve for $x$ $2.5x+3(\displaystyle \frac{4}{3}-\frac{5}{6}x)=4$ $2.5x+4-\displaystyle \frac{5}{2}x=4\qquad $... since $\displaystyle \frac{5}{2}=2.5$, we have $4=4$ The variable has vanished, and the resulting equation is a true one, so the system has infinitely many solutions.
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