Chapter 6 - Systems of Equations and Inequalities - 6-1 Solving Systems by Graphing - Lesson Check - Page 367: 3

(-1,0)

$y=−3x−3$ $y=2x+2$ Multiply the top equation by $−1$ so that the y values cancel, then you'll have $0=5x+5$ so subtract $ 5$ from both sides to have $−5=5x$ Then on both sides, divide by $5$ to get $x=−1$ Plug in $−1$ for the x value of either equation $y=−3(−1)−3$ to find that $y=0$