Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 5 - Linear Functions - 5-6 Parallel and Perpendicular Lines - Got It? - Page 332: 2

Answer

a) Neither opposite reciprocals nor perpendicular. b) Parallel

Work Step by Step

a) Find the slope of each line by writing their equation in slope-intercept form: $4x-3y=9$ $3y=4x-9$ $y=\frac{4}{3}x-3$ The slope of the graph of $y=\frac{4}{3}x-3$ is $\frac{4}{3}$ The slope of the graph of $y=\frac{3}{4}x+7$ is $\frac{3}{4}$ The slopes are not the same, so the lines cannot be parallel. Multiply the slopes: $\frac{4}{3}\times\frac{3}{4}=1$. The slopes are neither opposite reciprocals nor perpendicular. b) Find the slope of each line by writing their equation in slope-intercept form. $6y=-x+6$ $y=\frac{-1}{6}x+1$ The slope of the graph of $y=\frac{-1}{6}x+1$ is $\frac{-1}{6}$ The slope of the graph of $y=-\frac{1}{6}x+6$ is $\frac{-1}{6}$ The slopes are the same, so the lines will be parallel.
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