Answer
1. The second term is 16
2. The third term is 19
3. The fourth term is 22
4. The explicit formula is $A(n)=13+3(n-1)$
Work Step by Step
We are given:
$A(1)=13$
$A(n)=A(n-1)+3$
1. The second term is
$A(2)=A(2-1) +3 = A(1)+3 =13 +3= 16$
2. The third term is
$A(3)=A(3-1)+3 = A(2)+3 = 16+3= 19$
3. The fourth term is
$A(4)=A(4-1)+3 = A(3)+3 = 19 +3 = 22$
4. The explicit formula is $A(n)=13+3(n-1)$