Answer
$42+65+x\ge160$
at least $53$ cans
Work Step by Step
Let $x$ be the number of cans of food to be collected on Friday. Then the conditions of the problem can be represented by
$$
42+65+x\ge160
.$$
Using the properties of inequality, the solution to the inequality above is
$$\begin{aligned}
42+65+x&\ge160
\\
107+x&\ge160
\\
x&\ge160-107
\\
x&\ge53
.\end{aligned}
$$
Hence, the number of cans to be collected on Friday, $x$, should be at least $53$ cans.
