Answer
$y\lt- \frac{20}{3}$ or $y \gt \frac{38}{4}$
Work Step by Step
$\frac{4y+2}{5}-5\gt3$ or $\frac{4-3y}{6}\gt4$
For: $\frac{4y+2}{5}-5\gt3$
First, solve for y. Add 5 to both sides:
$\frac{4y+2}{5} \gt 8$
Multiply 5 on both sides:
$4y+2 \gt 40$
Subtract 2 from both sides:
$4y \gt 38$
Divide both sides by 4
$y \gt \frac{38}{4}$
For: $\frac{4-3y}{6}\gt4$
Multiply 6 on both sides:
$4-3y \gt 24$
Subtract 4 from both sides:
$-3y \gt 20$
Divide both sides by -3
$y\lt- \frac{20}{3}$
The solutions are $y\lt- \frac{20}{3}$ or $y \gt \frac{38}{4}$
