Answer
$-21\leq q \leq 33$
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Work Step by Step
Given: $-3 \leq \frac{6-q}{9} \leq 3$
$-27 \leq 6- q \leq 27$
Subtract 6 from each part.
$33 \geq q$ or $q \geq - 21$
The solutions as a single inequality are:
$-21\leq q \leq 33$
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