Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 3 - Solving Inequalities - 3-3 Solving Inequalities Using Multiplication or Division - Practice and Problem-Solving Exercises - Page 182: 59

Answer

If the least expensive snack is bought, you can afford at most 15 snacks.

Work Step by Step

Step 1) If the most expensive sandwiches and drinks are ordered, the cost is: 3(7) + 3(2) = 27 Step 2) If the least expensive sandwiches and drinks are ordered, the cost is: 3(4) + 3(1) = 15 Step 3) If the total bill is $15 (least expensive sandwiches), we would still have 15 left, so we could buy 15 more snacks.
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