Answer
$1, 2, 3,$ or $4$ cases
Work Step by Step
Let $x$ be the number of cases of vegetables the club can buy. Since a case of vegetables costs $\$10.68$ and the club can spend at most $\$50$, then
$$
10.68x\le50
.$$
Using the properties of equality, then
$$\begin{aligned}
\frac{10.68x}{10.68}&\le\frac{50}{10.68}
\\
x&\le4.68
.\end{aligned}
$$
Hence, the possible number of cases of vegetables the club can buy is $1, 2, 3,$ or $4$ cases.
