Answer
$\frac{1}{3}$$\lt$$f$
Work Step by Step
$0\lt-\frac{1}{3}+f$
Isolate f by add $\frac{1}{3}$ to both sides
$0+\frac{1}{3}\lt-\frac{1}{3}+\frac{1}{3}+f$
$\frac{1}{3}$$\lt$$f$
To check, make sure that a number that is greater than $\frac{1}{3}$
$f=1$
$\frac{1}{3}$$\lt$$1$
$true$
$\frac{1}{3}$$\lt$$f$